需要发邮件问的问题列表

问问题

1、这个表达中，为什么可以直接 L->next = p;
这个表示的是L的next指针指向p的什么？

LinkedList LinkedListCreatH()
{
    Node *L;
    L = (Node *)malloc(sizeof(Node));   //申请头结点空间
    L->next = NULL;                      //初始化一个空链表
    ElemType x;                         //x为链表数据域中的数据
    while(scanf("%d",&x) != EOF)
    {
        Node *p;
        p = (Node *)malloc(sizeof(Node));   //申请新的结点 
        p->data = x;                     //结点数据域赋值 
        p->next = L->next;                    //将结点插入到表头L-->|2|-->|1|-->NULL 
        L->next = p; 
    }
    return L; 
} 

2、输出下列三个值的不同，并标明输出的内容表示什么(表达是否正确)：

int main() {
  int i=0,o=2;
  int *pi =&i;                  //pi的内存指针指向i的地址
  printf("*pi :%i\n", *pi );
  *pi =1;                       //pi的内存指向1
  printf("%i\n", i );
  printf("pi:%p\n", pi );       //pi的内存地址
  pi=&o;                           //pi等于o的地址？？？
  printf("%i\n", pi);            //输出pi的值
  printf("%p\n", pi);           //输出指针pi储存的o的地址？？？
  printf("%i\n", *pi);          //输出pi所指内存中的值(&o的地址)，然后就等于*&o=2
  printf("%p\n", *pi);          //输出指针pi
  return 0;
}

3、在使用指针时出现了这样的error，无法解决

lianbiao.c: In function ‘main’:
lianbiao.c:17:5: error: ‘*l’ is a pointer; did you mean to use ‘->’?
l ->next = NULL;
^~
->
lianbiao.c:22:14: error: ‘*new_node’ is a pointer; did you mean to use ‘->’?
new_node -> next = l ->next;
^~
->
lianbiao.c:22:26: error: ‘*l’ is a pointer; did you mean to use ‘->’?
new_node -> next = l ->next;
^~
->
lianbiao.c:23:14: error: ‘*new_node’ is a pointer; did you mean to use ‘->’?
new_node ->num = x ;
^~
->
lianbiao.c: In function ‘delete’:
lianbiao.c:31:33: error: ‘*entry’ is a pointer; did you mean to use ‘->’?
for (size_t i = 1; i < entry->num -1; i++) {
^~
->
lianbiao.c:32:20: error: ‘*list’ is a pointer; did you mean to use ‘->’?
list = list->next;
^~
->
lianbiao.c:38:16: error: ‘*list’ is a pointer; did you mean to use ‘->’?
list = list->next;
^~
->
lianbiao.c:39:17: error: ‘*list’ is a pointer; did you mean to use ‘->’?
list = list ->next;
^~
->
lianbiao.c:41:7: error: ‘*o’ is a pointer; did you mean to use ‘->’?
o ->next = p;
^~
->

#include <stdio.h>
#include <stdlib.h>
typedef struct _list_t {
  int num;
  struct _list_t *next;
}*list_t;
list_t *delete(list_t* l,list_t *entry) ;
int main() {
  list_t *l;
  list_t *new_node;
  list_t *list;
  list_t *entry;
  scanf("%i", l );
  l ->next = NULL;
  int x;
  while (scanf(" %i ", &x ) != EOF) {
    list_t *n;
    new_node=(list_t*)malloc(sizeof(list_t));
    new_node -> next = l ->next;
    new_node ->num = x ;
  }
  return 0;
}
list_t *delete(list_t *l,list_t *entry) {
    list_t *list;
    list = l;
    for (size_t i = 1; i < entry->num -1; i++) {
        list = list->next;
    }
    list_t *o,*p,*q;
    o = (list_t*)malloc(sizeof(list_t));
    *o = *list;
    p = (list_t*)malloc(sizeof(list_t));
    list = list->next;
    list = list ->next;
    *p = *list ;
    o ->next = p;
    return l;
}