第7章作业

未分类

1、采用单向链表建立一个学生信息表，每个节点包括学号sno(int型)，姓名sname（字符型20位），成绩sscore(int型)，并输出。

#include<iostream>
#include <stdio.h>
#include<stdlib.h>
using namespace std;
struct ListNode{
    int sno;
    char sname[20];
    int sscore;
    struct ListNode* next;
};
struct ListNode* newnode(int n);
//void  deletenode(struct LinkNode* node);
//struct LinkNode* searchnode(struct LinkNode *node);
//struct LinkNode* insertnode(struct LinkNode* node);
void printnode(struct ListNode* head);
int main(){
    ListNode* head;
    head=newnode(3);
    printnode(head);
    return 0;
}
struct ListNode* newnode(int n){
    ListNode* temp;
    ListNode* head;
    for(int i=1;i<n;i++){//从一开始是因为第一次循环为头结点和下一个节点赋值了
        if(i==1){
            head=new ListNode;
            temp=head;
            cin>>head->sno>>head->sname>>head->sscore;
        }
            temp->next=new ListNode;
            temp=temp->next;
            cin>>temp->sno>>temp->sname>>temp->sscore;
    }
    temp->next=NULL;//如果为节点分配了空间再让他等于NULL好像不可以
    return head;
}
//void  deletenode(struct ListNode* node){}
//struct ListNode* searchnode(struct ListNode *node){}
//struct ListNode* insertnode(struct ListNode* node){}
void printnode(struct ListNode* head){
    while(head!=NULL){
        cout<<head->sno<<" "<<head->sname<<"  "<<head->sscore;
        head=head->next;
    }
}

2、P211 第11题

#include<iostream>   
using namespace std;  
int main()  
{  
    enum weekday{sun,mon,tus,wed,thu,fri,sat};  
    enum weekday day;  
    int a,b,c,d,e,f,g,loop;  
    char ch='A';  
    f=thu;  
    for(a=sun;a<=sat;a++)  
        if(a!=f)           
            for(b=sun;b<=sat;b++)  
                if((a!=b)&&(f>b))  
                    for(c=sun;c<=sat;c++)  
                       if((c!=a)&&(c!=b)&&(c!=f)&&(a==c+1)&&(f<c))   
                           for(d=sun;d<=sat;d++)  
                              if((d!=a)&&(d!=b)&&(d!=c)&&(d!=f)&&(c==d+3))  
                                  for(e=sun;e<=sat;e++)  
                                      if((e!=a)&&(e!=b)&&(e!=c)&&(e!=d)&&(e!=f)&&(d==e+2)) 
                                          for(g=sun;g<=sat;g++)   
                                              if((g!=a)&&(g!=b)&&(g!=c)&&(g!=d)&&(g!=e)&&(g!=f)&&(g==b+2))   
                                                  for(loop=0;loop<7;loop++)  
                                                  {   cout<<"Doctor"<<char(ch+loop)<<":";  
                                                      switch(loop+1)  
                                                      {  
                                                      case 1:day=weekday(a);break;  
                                                      case 2:day=weekday(b);break;  
                                                      case 3:day=weekday(c);break;  
                                                      case 4:day=weekday(d);break;  
                                                      case 5:day=weekday(e);break;  
                                                      case 6:day=weekday(f);break;  
                                                      case 7:day=weekday(g);break;  
                                                      }  
                                                       switch(day)  
                                                      {  
                                                      case sun:cout<<"Sunday"<<endl;break;  
                                                      case mon:cout<<"Monday"<<endl;break;  
                                                      case tus:cout<<"Thusday"<<endl;break;  
                                                      case wed:cout<<"Wednesday"<<endl;break;  
                                                      case thu:cout<<"Thurday"<<endl;break;  
                                                      case fri:cout<<"Friday"<<endl;break;  
                                                      case sat:cout<<"Saturday"<<endl;break;  
                                                      }  
                                                  }  
    return 0;  
} 

3、（选做）模拟一个用于显示时间的电子时钟。该时钟以时、分、秒的形式记录时间。试编写三个函数:setTime函数用于设置时钟的时间。increase函数模拟时间过去了1秒。showTime 显示当前时间，显示格式为HH:MM:SS。

#include<iostream>
#include<ctime>
#include<stdlib.h>
using namespace std;
struct clock{
    int hour;
    int minute;
    int second;
};
class clock_time{
    public:
        void setTime();
        void increase();
        void showTime();
    private:
        struct clock current_time;
};
void clock_time::setTime(){
    time_t rawtime;
    struct tm *info;
    time( &rawtime );
    info = localtime( &rawtime );
    current_time.hour=info->tm_hour;
    current_time.minute=info->tm_min;
    current_time.second=info->tm_sec;
}
void clock_time::increase(){
        setTime();
}
void clock_time:: showTime(){
        while(1){
            increase();
            system("clear");
            cout<<current_time.hour<<":"<<current_time.minute<<":"<<current_time.second<<endl;
        }
}
int main(){
    clock_time MyClock;
    MyClock.showTime();
    return 0;
}